2024 OscillationsAmplitude and Time Period in SHM Easy Question 8 of 63 in Oscillations

If $x=5\sin\left(\pi t + \frac{\pi}{3}\right)$ m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are;

A 5 cm, 1 s
B 5 m, 1 s
C 5 cm, 2 s
D 5 m, 2 s

The answer is D.

Solution

Comparing with $x = A\sin(\omega t + \phi)$: A = 5 m and $\omega = \pi$ rad $s^{-1}$ $T = \frac{2\pi}{\omega} = \frac{2\pi}{\pi} = 2$ s So amplitude = 5 m and time period = 2 s.

Concept Reading amplitude and time period from SHM equation

Oscillations in past papers

63 questions from this chapter have appeared across 26 exam years.