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The frequency of a light wave in a material is $2 \times 10^{14}$ Hz and wavelength is 5000 Å. The refractive index of material will be
A
1.50
B
3.00
C
1.33
D
1.40
Detailed Solution
Speed of the wave in the material: $v = n\lambda$, where $n$ is the frequency.
Here $n = 2 \times 10^{14}$ Hz and $\lambda = 5000$ Å $= 5000 \times 10^{-10}$ m
$v = 2 \times 10^{14} \times 5000 \times 10^{-10}$
$v = 10^{8}$ m/s
Refractive index of the material: $\mu = \dfrac{c}{v}$
$\mu = \dfrac{3 \times 10^{8}}{10^{8}} = 3$
Here $n = 2 \times 10^{14}$ Hz and $\lambda = 5000$ Å $= 5000 \times 10^{-10}$ m
$v = 2 \times 10^{14} \times 5000 \times 10^{-10}$
$v = 10^{8}$ m/s
Refractive index of the material: $\mu = \dfrac{c}{v}$
$\mu = \dfrac{3 \times 10^{8}}{10^{8}} = 3$