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Refractive Index
Concepts tested here
- Speed of light in a medium
All Questions
2007 AIPMT-PRE 1 question
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The frequency of a light wave in a material is $2 \times 10^{14}$ Hz and wavelength is 5000 Å. The refractive index of material will beSpeed of the wave in the material: $v = n\lambda$, where $n$ is the frequency.
Here $n = 2 \times 10^{14}$ Hz and $\lambda = 5000$ Å $= 5000 \times 10^{-10}$ m
$v = 2 \times 10^{14} \times 5000 \times 10^{-10}$
$v = 10^{8}$ m/s
Refractive index of the material: $\mu = \dfrac{c}{v}$
$\mu = \dfrac{3 \times 10^{8}}{10^{8}} = 3$