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For a transistor $\dfrac{I_C}{I_E} = 0.96$, then current gain for common emitter configuration : -
A
12
B
6
C
48
D
24
Detailed Solution
$\alpha = \dfrac{I_C}{I_E} = 0.96$ (current gain in common base configuration).
Current gain in common emitter configuration: $\beta = \dfrac{I_C}{I_B}$. Since $I_E = I_B + I_C$, $\beta = \dfrac{\alpha}{1 - \alpha}$
$\beta = \dfrac{0.96}{1 - 0.96} = \dfrac{0.96}{0.04} = 24$
Current gain in common emitter configuration: $\beta = \dfrac{I_C}{I_B}$. Since $I_E = I_B + I_C$, $\beta = \dfrac{\alpha}{1 - \alpha}$
$\beta = \dfrac{0.96}{1 - 0.96} = \dfrac{0.96}{0.04} = 24$