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For a transistor if $\dfrac{I_C}{I_E} = 0.98$ then current gain for common emitter circuit will be :-
A
49
B
98
C
4.9
D
25.5
Detailed Solution
$\alpha = \dfrac{I_C}{I_E} = 0.98$
Common emitter current gain: $\beta = \dfrac{I_C}{I_B} = \dfrac{\alpha}{1 - \alpha}$
$\beta = \dfrac{0.98}{0.02} = 49$
Common emitter current gain: $\beta = \dfrac{I_C}{I_B} = \dfrac{\alpha}{1 - \alpha}$
$\beta = \dfrac{0.98}{0.02} = 49$
