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Transistor Current Gains
Appears in
Concepts tested here
- Relation between alpha and beta 2
- Beta from alpha
All Questions
2002 AIPMT 1 question
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For a transistor $\dfrac{I_C}{I_E} = 0.96$, then current gain for common emitter configuration : -$\alpha = \dfrac{I_C}{I_E} = 0.96$ (current gain in common base configuration).
Current gain in common emitter configuration: $\beta = \dfrac{I_C}{I_B}$. Since $I_E = I_B + I_C$, $\beta = \dfrac{\alpha}{1 - \alpha}$
$\beta = \dfrac{0.96}{1 - 0.96} = \dfrac{0.96}{0.04} = 24$
2001 AIPMT 1 question
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For a transistor if $\dfrac{I_C}{I_E} = 0.98$ then current gain for common emitter circuit will be :-$\alpha = \dfrac{I_C}{I_E} = 0.98$
Common emitter current gain: $\beta = \dfrac{I_C}{I_B} = \dfrac{\alpha}{1 - \alpha}$
$\beta = \dfrac{0.98}{0.02} = 49$
2000 AIPMT 1 question
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The correct relation for $\alpha$, $\beta$ for a transistor :$\alpha = \dfrac{I_C}{I_E}$ and $\beta = \dfrac{I_C}{I_B}$, with $I_E = I_B + I_C$.
$\beta = \dfrac{I_C}{I_E - I_C} = \dfrac{I_C/I_E}{1 - I_C/I_E}$
$\beta = \dfrac{\alpha}{1 - \alpha}$
(Equivalently $\alpha = \dfrac{\beta}{1 + \beta}$.)
