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Semiconductor Electronics: Materials, Devices and Simple Circuits
Diode in a Circuit
1 question from 1 paper, each with its answer.
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Concepts tested
- Reverse biased branch carries no current
All Questions
2001 AIPMT 1 question
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The current (I) in the circuit will be : -
Check the bias of each diode with respect to the battery.
The diode in the top (20 $\Omega$) branch is reverse biased, so it acts as an open switch and no current flows in that branch.
The diode in the middle (30 $\Omega$) branch is forward biased and acts as a closed switch (ideal diode).
So the equivalent circuit is the 5 V battery in series with 20 $\Omega$ and 30 $\Omega$.
$I = \dfrac{5\ V}{(30 + 20)\ \Omega} = \dfrac{5}{50}$ A