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Units and Measurements
Dimensional Formula
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- Dimensions of G
All Questions
2004 AIPMT 1 question
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The dimensions of universal gravitational constant are :-Newton's law of gravitation: $F = \dfrac{Gm_1m_2}{r^2}$
$\therefore G = \dfrac{Fr^2}{m_1m_2}$
$[G] = \dfrac{[F][r^2]}{[m^2]} = \dfrac{MLT^{-2} \cdot L^2}{M^2}$
$= M^{-1}L^3T^{-2}$
So the dimensions of the universal gravitational constant are $M^{-1}L^3T^{-2}$.