2022 Phase 2 Units and MeasurementsPropagation of errors Easy Question 21 of 53 in Units and Measurements

The percentage error in the measurement of g is: (Given that $g=\frac{4\pi^2L}{T^2}$, $L=(10\pm0.1)$ cm, $T=(100\pm1)$ s)

A 7%
B 2%
C 5%
D 3%

The answer is D.

Solution

$\frac{\Delta g}{g}\times100=\frac{\Delta L}{L}\times100+2\frac{\Delta T}{T}\times100=\left(\frac{0.1}{10}\times100\right)+2\left(\frac{1}{100}\times100\right)=1+2=3\%$.

Concept Propagation of errors

Units and Measurements in past papers

53 questions from this chapter have appeared across 25 exam years.