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Wave Optics
Bragg's Law of Diffraction
1 question from 1 paper, each with its answer.
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Concepts tested
- Maximum wavelength from Bragg's law
All Questions
2001 AIPMT 1 question
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The interplanar distance in a crystal is $2.8 \times 10^{-8}$ m. The value of maximum wavelength which can be diffracted : -Bragg's law: $2d\sin\theta = n\lambda$
Since $\sin\theta \leq 1$, for the first order (n = 1): $\lambda \leq 2d$
Therefore $\lambda_{max} = 2d = 2 \times 2.8 \times 10^{-8}$ m
$\lambda_{max} = 5.6 \times 10^{-8}$ m