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If $V_{1}$ is velocity of a body projected from the point A and $V_{2}$ is the velocity of a body projected from point B which is vertically below the highest point C. if both the bodies collide, then
Explanation
Two bodies will collide at the highest point if both cover the same vertical height in the same time. $So \frac{V_{1}^{2}\sin^{2} 30^{\circ}}{2g} = \frac{V_{2}^{2}}{2g} \Rightarrow \frac{V^{2}}{V^{1}} = \sin 30^{\circ} = 1/2$ $\therefore V_{2} = (1/2)V_{1}$