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The velocity of a projectile at the initial point A is $(2\hat{i} + 3\hat{j})m/s$ its velocity (in $m/s$ ) at point B is [add image]
Explanation
At point B the direction of velocity component of the projectile along Y-axis reverses. Hence, $\vec{V}_{B} = 2\hat{i} - 3\hat{j}$
