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A body is thrown with a velocity of $9.8 ms^{-1}$ making an angle of $30^{\circ}$ with the horizontal. It will hit the ground after a time
Explanation
Time of flight = $2u \sin \theta/g = (2 \times 9.8 \times \sin 30^{\circ})/9.8 = 2 \times (1/2) = 1\text{sec}$