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Two balls are projected at an angle $\theta$ and $(90^{\circ} - \theta)$ to the horizontal with the same speed. The ratio of their maximum vertical heights is
Explanation
$H_{1}/H_{2} = (u^{2}\sin^{2} \theta/2g) / (u^{2}\sin^{2}(90^{\circ}-\theta)/2g) = \tan^{2} \theta$