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The velocity of projection of a body is increased by 2%. Other factors remaining unchanged, what will be the percentage change in the maximum height attained?
Explanation
We know that, $y_{m} = H = (u \sin \theta)^{2}/2g = u^{2}\sin^{2} \theta/2g$ $\therefore \Delta H/H = 2\Delta u/u$. Given $\Delta u/u = 2\%$ $\therefore \Delta H/H = 2 \times 2 = 4\%$