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A ball released from a height falls 5 m in one second. In 4 seconds it falls through
Explanation
Since $S = ut + 1/2g^{2}$ where u is initial velocity &a is acceleration. In this case $u = 0$&$a = g$ so distance travelled in 4sec is, $S = 1/2 \times 10 \times 16 = 80 m$
