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A body released from the top of a tower falls through half the height of the tower in 2 s. In what time shall the body fall through the height of the tower?
Explanation
For constant acceleration and zero initial velocity $h \propto t^{2}$ $h_{1}/h_{2} = t_{1}^{2}/t_{2}^{2} \Rightarrow t_{2} = \sqrt{h_{2}/h_{1}} t_{1} = \sqrt{2} \times t_{1} = \sqrt{2} \times 2s$