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A stone falls from a balloon that is descending at a uniform rate of $12 m/s$. The displacement of the stone from the point of release after 10sec is
Explanation
$u = 12 m/s$, $g = 9.8 m/\text{sec}^{2}$, $t = 10\text{sec}$ Displacement = $ut + \frac{1}{2}gt^{2}$ = $12 \times 10 + \frac{1}{2} \times 9.8 \times 100 = 610 m$