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A stone thrown upward with a speed u from the top of the tower reaches the ground with a velocity 3u. The height of the tower is
Explanation
The stone rises up till its vertical velocity is zero and again reached the top of the tower with a speed u (downward). The speed of the stone at the base is 3u. Hence $(3u)^{2} = (-u)^{2} + 2gh$ or $h = 4u^{2}/g$
