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A ball dropped from a point A falls down vertically to C, through the midpoint B. The descending time from A to B and that from A to C are in the ratio
Explanation
For A to B $S = \frac{1}{2}gt^{2}$ For A to C $2S = \frac{1}{2}gt'^{2}$ Dividing (i) by (ii) we get $t/t' = 1/\sqrt{2}$