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Which one of the following biomolecules is correctly characterised?
A
Alanine amino acid – Contains an amino group and an acidic group anywhere in the molecule
B
Lecithin – a phosphorylated glyceride found in cell membrane
C
Palmitic acid – an unsaturated fatty acid with 18 carbon atoms
D
Adenylic acid – adenosine with a glucose phosphate molecule
Detailed Solution
Lecithin is a phospholipid: a glyceride in which phosphorus and a phosphorylated organic compound are present; it is found in the cell membrane. This description is correct.
Alanine is an $\alpha$-amino acid: the amino group and the carboxyl (acidic) group are both attached to the same carbon, the $\alpha$-carbon, not anywhere in the molecule.
Palmitic acid is a saturated fatty acid with 16 carbon atoms (including the carboxyl carbon), not an unsaturated 18-carbon acid.
Adenylic acid is a nucleotide: adenosine (adenine + ribose) with a phosphate group, not with glucose phosphate.
Hence only lecithin is correctly characterised.
Alanine is an $\alpha$-amino acid: the amino group and the carboxyl (acidic) group are both attached to the same carbon, the $\alpha$-carbon, not anywhere in the molecule.
Palmitic acid is a saturated fatty acid with 16 carbon atoms (including the carboxyl carbon), not an unsaturated 18-carbon acid.
Adenylic acid is a nucleotide: adenosine (adenine + ribose) with a phosphate group, not with glucose phosphate.
Hence only lecithin is correctly characterised.