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Chemical Bonding and Molecular Structure
Shapes of Molecules: Octahedral Geometry
1 question from 1 paper, each with its answer.
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Concepts tested
- Trans bond angles in octahedron
All Questions
2004 AIPMT 1 question
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In a regular octahedral molecule, $MX_6$ the number of X–M–X bonds at $180^\circ$ is :-In a regular octahedron, the six X atoms lie along the $+x$, $-x$, $+y$, $-y$, $+z$ and $-z$ axes around M.
An X–M–X angle of $180^\circ$ occurs only between two X atoms on opposite ends of the same axis (trans positions).
The pairs are: $+x$ and $-x$, $+y$ and $-y$, $+z$ and $-z$.
All other pairs of X atoms (cis pairs, 12 in number) make $90^\circ$ angles.
So the number of X–M–X bonds at $180^\circ$ is three.