2022 Alternating CurrentAC Voltage – Peak and RMS Values Easy Question 18 of 60 in Alternating Current

The peak voltage of the ac source is equal to

A $\frac{1}{\sqrt{2}}$ times the rms value of the source
B the value of voltage supplied to the circuit
C the rms value of the ac source
D $\sqrt{2}$ times the rms value of the source

The answer is D.

Solution

For a sinusoidal ac: $V_{rms} = \frac{V_0}{\sqrt{2}}$ So the peak voltage $V_0 = \sqrt{2} \times V_{rms}$, i.e. $\sqrt{2}$ times the rms value of the source.

Concept peak vs rms voltage

Alternating Current in past papers

60 questions from this chapter have appeared across 24 exam years.