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An inductor of inductance 2 mH is connected to a 220 V, 50 Hz a.c. source. Let the inductive reactance in the circuit is $X_1$. If a 220 V dc source replaces the ac source in the circuit, then the inductive reactance in the circuit is $X_2$. $X_1$ and $X_2$ respectively are
Detailed Solution
For AC: $X_1=\omega L=2\pi fL=2\pi\times50\times2\times10^{-3}=0.628\ \Omega$. For DC, $f=0$, so $X_2=2\pi fL=0$.