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A standard filament lamp consumes 100 W when connected to 200 V ac mains supply. The peak current through the bulb will be:
Detailed Solution
$i_{rms}=\frac{P}{V_{rms}}=\frac{100}{200}=\frac{1}{2}$ A. $i_0=\sqrt{2}\,i_{rms}=\frac{\sqrt{2}}{2}=\frac{1}{\sqrt{2}}\approx0.707$ A.