Solution

For a conducting sphere: $E = \frac{\sigma}{\epsilon_0}$ and $V = \frac{\sigma R}{\epsilon_0}$ When connected by a wire, both spheres have the same potential: $V_1 = V_2$ $\sigma_1R_1 = \sigma_2R_2 \Rightarrow \frac{\sigma_1}{\sigma_2} = \frac{R_2}{R_1}$

Concept surface charge density ratio

Electrostatic Potential and Capacitance in past papers

76 questions from this chapter have appeared across 27 exam years.