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Six charges $+q$, $-q$, $+q$, $-q$, $+q$ and $-q$ are fixed at the corners of a hexagon of side d as shown in the figure. The work done in bringing a charge $q_0$ to the centre of the hexagon from infinity is: ($\varepsilon_0$ - permittivity of free space)
Detailed Solution
All six charges are at the same distance d from the centre; three are $+q$ and three are $-q$, so the potential at the centre $V_0=0$. Work done $W_{\infty\rightarrow0}=q_0\Delta V=q_0(0)=0$.