The value of electric potential at a distance of 9 cm from the point charge $4\times10^{-7}$ C is [Given $\dfrac{1}{4\pi\varepsilon_0}=9\times10^9\ N\,m^2\,C^{-2}$]:

A $4\times10^2$ V

B 44.4 V

C $4.4\times10^5$ V

D $4\times10^4$ V

The answer is D.

Solution

$V=\dfrac{kq}{r}=\dfrac{9\times10^9\times4\times10^{-7}}{9\times10^{-2}}=4\times10^4$ V.

Concept Electric potential due to a point charge

76 questions from this chapter have appeared across 27 exam years.