2023 Electrostatic Potential and CapacitancePotential due to an Electric Dipole Medium Question 16 of 76 in Electrostatic Potential and Capacitance

An electric dipole is placed as shown in the figure. The electric potential (in 10² V) at point P due…

An electric dipole is placed as shown in the figure.

The electric potential (in $10^2\ V$) at point P due to the dipole is ($\epsilon_0$ = permittivity of free space and $\frac{1}{4\pi\epsilon_0}=K$):
A $\left(\frac{8}{3}\right)qK$
B $\left(\frac{3}{8}\right)qK$
C $\left(\frac{5}{8}\right)qK$
D $\left(\frac{8}{5}\right)qK$

The answer is B.

Solution

$V_P=V_{+q}+V_{-q}=\left(\frac{Kq}{2}-\frac{Kq}{8}\right)\times10^2=\frac{3Kq}{8}\times10^2$.

$V_P=V_q+V_{-q}$ $=\left(\frac{Kq}{5-3}+\frac{K(-q)}{5+3}\right)\times10^2$ $=\left(\frac{Kq}{2}-\frac{Kq}{8}\right)\times10^2$ $=\left(\frac{3Kq}{8}\right)\times10^2$

Concept potential at a point on dipole axis

Electrostatic Potential and Capacitance in past papers

76 questions from this chapter have appeared across 27 exam years.