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If a conducting sphere of radius R is charged. Then the electric field at a distance r(r > R) from the centre of the sphere would be, (V = potential on the surface of the sphere)
A
$\dfrac{rV}{R^2}$
B
$\dfrac{R^2V}{r^3}$
C
$\dfrac{RV}{r^2}$
D
$\dfrac{V}{r}$
Detailed Solution
$V=\dfrac{KQ}{R}\Rightarrow KQ=VR$. $E=\dfrac{KQ}{r^2}=\dfrac{VR}{r^2}$.