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The electrostatic force between the metal plates of an isolated parallel plate capacitor C having a charge Q and area A, is
Explanation
$F = Q^2/2A\varepsilon_0$ contains no d.
Detailed Solution
For an isolated capacitor, Q = constant.
$F_{plate} = \frac{Q^2}{2A\varepsilon_0}$
So F is independent of the distance between the plates.