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The output ($Y$) of the given logic gate is similar to the output of an/a:
A
OR gate
B
AND gate
C
NAND gate
D
NOR gate
Detailed Solution
[add image: logic circuit – NAND gate on A, NOR gate on B, both feeding a final NOR gate]
NAND gate with both inputs A gives $\bar{A}$; NOR gate with both inputs B gives $\bar{B}$.
Final gate output: $Y = \overline{\bar{A} + \bar{B}} = \bar{\bar{A}} \cdot \bar{\bar{B}} = A \cdot B$
So the output is similar to that of an AND gate.