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A logic circuit provides the output $Y$ as per the following truth table:
A
$\bar{B}$
B
$B$
C
$A.B + \bar{A}$
D
$A.\bar{B} + \bar{A}$
Detailed Solution
From the truth table, Y = 1 whenever B = 0 and Y = 0 whenever B = 1, independent of A.
So the output Y is just the inverse of B: $Y = \bar{B}$