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All Exams › NEET Previous Year Questions › Physics › Semiconductor Electronics: Materials, Devices and Simple Circuits › Light emitting diode › Question #3784
Semiconductor Electronics: Materials, Devices and Simple CircuitsLight emitting diode 1 2019 Odisha Easy
An LED is constructed from a p-n junction diode using GaAsP. The energy gap is 1.9 eV. The wavelength of the light emitted will be equal to:

Detailed Solution

$\lambda=\frac{12400}{1.9}$ Å $\approx6526$ Å $\approx654$ nm.

All Questions in Light emitting diode
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