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In the circuit shown below, the voltage appearing across the diode D will be of the form:
A
- 
B
- 
C
- 
D
- 
Detailed Solution
In the positive half cycle, the diode is reverse biased, so it is replaced by an open circuit and the full input voltage appears across the diode.
In the negative half cycle, the diode is forward biased, so it acts like a wire and the input voltage appears across R (voltage across the diode is zero).
So $v_D$ follows the input for the positive half cycle and is zero for the negative half cycle.