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Conservation of angular momentum – energy loss
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Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc with angular velocities $\omega_1$ and $\omega_2$. They are brought into contact face to face coinciding the axis of rotation. The expression for loss of energy during this process is
Loss = $\frac{1}{2}\frac{I_1I_2}{I_1+I_2}(\omega_1-\omega_2)^2$.
$\Delta KE = \frac{1}{2}\frac{I_1I_2}{I_1 + I_2}(\omega_1 - \omega_2)^2$ $= \frac{1}{2}\frac{I^2}{(2I)}(\omega_1 - \omega_2)^2$ $= \frac{1}{4}I(\omega_1 - \omega_2)^2$
