Solution

Lewis structure of $NO_3^-$: N is joined to one O by a double bond and to two O atoms by single bonds; the ion has 24 valence electrons.
Around nitrogen: one N=O double bond (2 bond pairs) + two N–O single bonds (2 bond pairs) = 4 bond pairs.
Nitrogen uses all 5 of its valence electrons plus the extra charge in bonding (one N–O bond is a coordinate bond), so it has no lone pair.
Hence N has 4 bond pairs and 0 lone pairs. (Its shape is trigonal planar, since only the 3 $\sigma$ bonds decide the shape.)

Concept Bond pairs and lone pairs around N in nitrate

Chemical Bonding and Molecular Structure in past papers

108 questions from this chapter have appeared across 27 exam years.