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A cricketer catches a ball of mass 150 gm in 0.1 second moving with speed 20 m s$^{-1}$. Then he experiences force of : -
A
300 N
B
30 N
C
3 N
D
0.3 N
Detailed Solution
Impulse = change in momentum, and average force $F = \dfrac{\Delta P}{\Delta t}$.
The ball comes to rest, so $\Delta P = mv = 150 \times 10^{-3} \times 20 = 3$ kg m/s
$F = \dfrac{3}{0.1} = 30$ N
The ball comes to rest, so $\Delta P = mv = 150 \times 10^{-3} \times 20 = 3$ kg m/s
$F = \dfrac{3}{0.1} = 30$ N