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A lift of mass 1000 kg which is moving with acceleration of 1 m/s$^2$ in upward direction, then the tension developed in string which is connected to lift is : -
A
9800 N
B
10,800 N
C
11000 N
D
10,000 N
Detailed Solution
Forces on the lift: tension T upward and weight mg downward. Net force gives the upward acceleration a:
$T - mg = ma \Rightarrow T = m(g + a)$
$T = 1000(9.8 + 1) = 1000 \times 10.8$
$T = 10,800$ N
$T - mg = ma \Rightarrow T = m(g + a)$
$T = 1000(9.8 + 1) = 1000 \times 10.8$
$T = 10,800$ N