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Motion in a lift
Concepts tested here
- Tension in an accelerating lift
All Questions
2011 AIPMT-PRE 1 question
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A person of mass 60 kg is inside a lift of mass 940 kg and presses the button on control panel. The lift starts moving upwards with an acceleration 1.0 m/$s^2$. If g = 10 m $s^{-2}$, the tension in the supporting cable isTotal mass supported by the cable = mass of lift + mass of person = 940 + 60 = 1000 kg.
Forces on the system: tension T upward and weight $(M + m)g$ downward.
The lift accelerates upward, so $T - (M + m)g = (M + m)a$
$T = (M + m)(g + a)$
$T = 1000\times(10 + 1) = 11000$ N