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Oscillations
Simple Harmonic Motion – Amplitude
1 question from 1 paper, each with its answer.
- question
- 1
- paper
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- years asked, 2017–2026
- 1 of 10
- of Oscillations
- 1.59%
Concepts tested
- amplitude of a superposition of sine and cosine terms
All Questions
2019 1 question
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The displacement of a particle executing simple harmonic motion is given by $y=A_0+A\sin\omega t+B\cos\omega t$. Then the amplitude of its oscillation is given by:$y=A_0+A\sin\omega t+B\cos\omega t$ Shifting origin: $y'=y-A_0=A\sin\omega t+B\cos\omega t$ The two SHMs have a phase difference of $90^\circ$, so the resultant amplitude is $R=\sqrt{A^2+B^2+2AB\cos90^\circ}=\sqrt{A^2+B^2}$
