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The given truth table is for which logic gate : -
A
NAND
B
XOR
C
NOR
D
OR
Detailed Solution
The output is 0 only when both inputs are 1, and 1 in all other cases.
This is the opposite (complement) of the AND gate output: $Y = \overline{A \cdot B}$
Check: AND gives 1, 0, 0, 0 for the four rows; its complement is 0, 1, 1, 1, which matches the table.
(XOR would give 0 for A = B = 0; NOR and OR do not match either.)
So the truth table is for the NAND gate.
This is the opposite (complement) of the AND gate output: $Y = \overline{A \cdot B}$
Check: AND gives 1, 0, 0, 0 for the four rows; its complement is 0, 1, 1, 1, which matches the table.
(XOR would give 0 for A = B = 0; NOR and OR do not match either.)
So the truth table is for the NAND gate.