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Given truth table is correct for :
A = 1, B = 1 : Y = 1
A = 1, B = 0 : Y = 0
A = 0, B = 1 : Y = 0
A = 0, B = 0 : Y = 0
A = 1, B = 1 : Y = 1
A = 1, B = 0 : Y = 0
A = 0, B = 1 : Y = 0
A = 0, B = 0 : Y = 0
A
NAND
B
AND
C
NOR
D
OR
Detailed Solution
The output is 1 only when both inputs are 1; otherwise it is 0.
This is the AND operation: $Y = A \cdot B$.
So the truth table is for the AND gate.
This is the AND operation: $Y = A \cdot B$.
So the truth table is for the AND gate.