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The potential difference $(V_A - V_B)$ between the points A and B in the given figure is:
A
+6 V
B
+9 V
C
–3 V
D
+3 V
Explanation
Walk from A to B subtracting IR drops and the cell emf.
Detailed Solution
$V_B = V_A - (2\times2) - 3 - (2\times1)$
$\Rightarrow V_A - V_B = 9$ V