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Two identical inductors are connected in two different configurations P and Q, where a time varying current I(t) is flowing, as shown in the figure. The induced emf between points a and b for configuration P is $E_P$ and that for configuration Q is $E_Q$. The ratio $E_P/E_Q$ is: [Neglect the effect of mutual inductance.]
Detailed Solution
In P, a and b are across one inductor carrying the full current: $E_P=L\frac{di}{dt}$. In Q, the current splits equally between the two parallel inductors: $E_Q=L\frac{d(i/2)}{dt}=\frac{L}{2}\frac{di}{dt}$. So $\frac{E_P}{E_Q}=2$.