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Work, Energy and Power
Collisions – Impulse
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Concepts tested
- impulse in an elastic rebound
All Questions
2021 1 question
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A ball of mass 0.15 kg is dropped from a height 10 m, strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is ($g=10\ m/s^2$) nearly:Velocity just before striking the ground: $v_1 = \sqrt{2gh} = \sqrt{2 \times 10 \times 10} = 10\sqrt{2}$ m/s (downward) It rebounds to the same height, so the speed just after is the same, $10\sqrt{2}$ m/s (upward). Impulse $= m|\Delta v| = 0.15 \times [10\sqrt{2} - (-10\sqrt{2})] = 0.15 \times 20\sqrt{2}$ $= 3\sqrt{2} \approx 4.2$ kg m/s