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Work, Energy and Power
Kinetic Energy in Free Fall
1 question from 1 paper, each with its answer.
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Concepts tested
- KE proportional to mass at equal velocity
All Questions
2004 AIPMT 1 question
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A ball of mass 2 kg and another of mass 4 kg are dropped together from a 60 feet tall building. After a fall of 30 feet each towards earth, their respective kinetic energies will be in the ratio of-Both balls are dropped from rest and fall the same height h = 30 ft. In free fall the velocity does not depend on mass.
Here $v_1 = v_2 = \sqrt{2gh}$
$\dfrac{KE_1}{KE_2} = \dfrac{\frac{1}{2}m_1v_1^2}{\frac{1}{2}m_2v_2^2} = \dfrac{m_1}{m_2}$
$= \dfrac{2}{4} = \dfrac{1}{2}$
So their kinetic energies are in the ratio 1 : 2.