Looking for classes? Ksquare Career Institute, Bengaluru →
In producing chlorine by electrolysis 100 kW power at 125 V is being consumed. How much chlorine per minute is liberated? (E.C.E. of chlorine is $0.367\times10^{-6}$ kg/C)
A
$3.67\times10^{-3}$ kg
B
$1.76\times10^{-3}$ kg
C
$9.67\times10^{-3}$ kg
D
$17.61\times10^{-3}$ kg
Detailed Solution
Current drawn: $I = \frac{P}{V} = \frac{100\times10^3}{125} = 800$ A
Time: t = 1 minute = 60 s
Faraday's first law: mass liberated $m = ZIt$
$m = 0.367\times10^{-6}\times800\times60$
$m = 0.367\times10^{-6}\times48000 = 17.6\times10^{-3}$ kg
$m \approx 17.61\times10^{-3}$ kg
Time: t = 1 minute = 60 s
Faraday's first law: mass liberated $m = ZIt$
$m = 0.367\times10^{-6}\times800\times60$
$m = 0.367\times10^{-6}\times48000 = 17.6\times10^{-3}$ kg
$m \approx 17.61\times10^{-3}$ kg