Looking for classes? Ksquare Career Institute, Bengaluru →
Drift of electrons
Concepts tested here
- Work done by electric field
All Questions
2009 AIPMT 1 question
-
The mean free path of electrons in a metal is $4\times10^{-8}$ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/mBetween two collisions the electron moves freely over the mean free path d and gains energy from the field.
Energy gained = work done by the field = force × distance = eEd
$eEd = 2$ eV, so $Ed = 2$ V
$E = \frac{2}{d} = \frac{2}{4\times10^{-8}}$
$E = 5\times10^7$ V/m