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Laws of Motion
Apparent Weight in a Lift
1 question from 1 paper, each with its answer.
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Concepts tested
- Apparent weight in accelerating lift
All Questions
2003 AIPMT 1 question
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A man weighs 80 kg. He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5 m/s$^2$. What would be the reading on the scale ? (g = 10 m/s$^2$)The scale reads the normal reaction N exerted on the man.
For the man moving up with acceleration a: $N - mg = ma$
Reading of weighing scale $= N = m(g + a)$
$= 80(10 + 5) = 80 \times 15 = 1200$ N
So the scale reads 1200 N (more than his true weight of 800 N).